9^2x(1/3)^x+2=27(3x)^-2

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Solution for 9^2x(1/3)^x+2=27(3x)^-2 equation: 



9^2x(1/3)^x+2=27(3x)^-2

We move all terms to the left:

9^2x(1/3)^x+2-(27(3x)^-2)=0



Domain of the equation: 3)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

9^2x(+1/3)^x-(273x^-2)+2=0

We get rid of parentheses

9^2x(+1/3)^x-273x^+2+2=0

We multiply all the terms by the denominator


9^2x(+1-273x^*3)^x+2*3)^x+2*3)^x=0

Wy multiply elements

18x^2+9^2x(+1-273x^*3)^x=0

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